(x^4y-2)/(x^-3y^5)(-1)

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Solution for (x^4y-2)/(x^-3y^5)(-1) equation: 


D( x )

x = 0

x^-3*y^5 = 0

x = 0

x = 0

x^-3*y^5 = 0

x^-3*y^5 = 0

x^-3*y^5 = 0 // : y^5

x^-3 = 0

x należy do O

x in (-oo:0) U (0:+oo)

-1*((x^4*y-2)/(x^-3*y^5)) = 0

-((x^4*y-2)/(x^-3*y^5)) = 0

(-1*(x^4*y-2))/(x^-3*y^5) = 0

( -1 )

-1 = 0

x belongs to the empty set

( x^4*y-2 )

x^4*y = 2 // : y

x^4 = 2/y

x^4 = 2/y // ^ 1/4

abs(x) = (2^(1/4))/(y^(1/4))

x = (2^(1/4))/(y^(1/4)) or x = -((2^(1/4))/(y^(1/4)))

x in { (2^(1/4))/(y^(1/4)), -((2^(1/4))/(y^(1/4))) }

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